BaOH
RMM: 137 + 16 + 1 = 154
moles = mass/rmm
2006-11-05 06:48:49 · 5 answers · asked by Joyce 4 in Science & Mathematics ➔ Chemistry
Ba is divalent , so the chemical formula is Ba(OH)2 .
then, molar mass of it = 137 + 2(16+1) = 171 gm
therefore Molarity = no. of moles = mass / molar mass = 17.1 / 171 = 0.1molar
2006-11-05 07:16:51 · answer #1 · answered by alhassan1404 1 · 0⤊ 0⤋
while you at the instant are not specific which equation to apply, circulate lower back to the definitions: concentration = quantity/quantity (consistently) extra in specific, Molarity (concentration mol/L) = moles/quantity in L Moles = mass/(molar mass) (consistently) = 372g/(molar mass of H3PO4) quantity = 455 x 10^-3 L you could now exchange and do the mathematics. significant: you do no longer ought to memorise numerous formulation in case you already know the thought.
2016-11-27 20:28:14 · answer #2 · answered by ? 4 · 0⤊ 0⤋
OK, remember molarity is moles per liter. So we need to convert the amount of BaOH into moles and the amount of water into liters. A cubic centimeter is the same as a milliliter. Multiplying by 10^3, I find that a cubic decimeter is the same as a liter, so we don't need to worry about that.
Now BaOH is 154 g/mol, as you've calculated. (Thanks! That made my job easier.) To calculate moles, multiply grams by moles/gram. That's the same as dividing by g/mol. So you have 17.1/154, or 0.111, g/L.
2006-11-05 07:04:54 · answer #3 · answered by Amy F 5 · 0⤊ 0⤋
# of moles of BaOH=17.1g * (1 mole BaOH/154.0g)=0.1110mols
we have 0.1110 mols in 1 dm3 and molarity = moles/vol
therefore molarity = 0.1110 mol dm-3
2006-11-05 07:07:15 · answer #4 · answered by toasteddeer 2 · 0⤊ 0⤋
ahhhhh, the sweet smell of homework questions on a Sunday night. nothing like it.
sorry, i don't remember. I don't know my mass from a mole in the ground! LOL! I kill me....
2006-11-05 06:56:31 · answer #5 · answered by OK yeah well whatever 4 · 1⤊ 0⤋