A group of 72 players from Roundball Camp and 56 players from Cenral League met to play basketball. Each GROUP must separate teams with the sAMe # OF PLAYERS .; What is the greatest # of people that could be on 1 team/????
2006-11-05 05:58:25 · 10 answers · asked by Anonymous in Sports ➔ Basketball
I'm too old to be doing your homework
2006-11-05 06:30:41 · answer #1 · answered by Tom 4 · 0⤊ 0⤋
In this problem, you're basically trying to find the GCF or greatest common factor of the group numbers of 72 and 56. So, to find the GCF, you must use prime factorization to separate 72 and 56 into their prime factors. 72=2 x 2 x 2 x 3 x 3 and 56 = 2 x 2 x 2 x 7. Since both numbers have 2 x 2 x 2, your answer is 8. The greatest number of people that can be on one team is 8.
2006-11-05 14:41:31 · answer #2 · answered by Evan L 2 · 0⤊ 0⤋
Roundball Camp has 2 teams of 36 people, and Central league has 2 teams of 28 people.
2006-11-05 14:20:33 · answer #3 · answered by tom l 1 · 0⤊ 0⤋
7
2006-11-05 14:06:30 · answer #4 · answered by life_will_be_ok 4 · 0⤊ 0⤋
16 teams with 8 players on each team.
2006-11-05 15:08:28 · answer #5 · answered by smitty 7 · 0⤊ 0⤋
8 players 8x9=72 and 8x7=56 thus the remaining 16 players could play against each other in teams of 8.
8 should be the correct answer.
2006-11-05 14:03:15 · answer #6 · answered by Anonymous · 1⤊ 0⤋
The great # of people on one team will be 16
2006-11-05 14:08:52 · answer #7 · answered by kurt2006 2 · 0⤊ 0⤋
79
2006-11-05 14:02:35 · answer #8 · answered by Mickey P- Legend 1 · 0⤊ 1⤋
64 players on each team
2006-11-05 14:00:31 · answer #9 · answered by mnkyinabarrel 2 · 0⤊ 1⤋
This is in the wrong section! And is that homework?
2006-11-05 17:01:51 · answer #10 · answered by *~*kirsten*~* 2 · 0⤊ 0⤋