This is for my kid. I couldn't do it. Please help!
2006-11-05 04:44:19 · 9 answers · asked by mammasmom 1 in Science & Mathematics ➔ Mathematics
2^n=81
log(2) 2^n=log(2) 81
n=log (2) 81
log (2) 81 is about 6.33985
2006-11-05 04:48:16 · answer #1 · answered by me8md 3 · 0⤊ 0⤋
(n + a million)/2 + (2n + a million)/3 = 9 {3(n + a million) + 2(2n + a million)} / 6 = 9 (3n + 3 + 4n + 2) / 6 = 9 (7n + 5) / 6 = 9 7n + 5 = 9 * 6 (multiplication) 7n + 5 = fifty 4 7n = fifty 4 - 5 7n = 40 9 n = 40 9 / 7 n = 7
2016-10-21 07:36:42 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Take ln both sides and use this property.
ln a^x = x ln a
ln 2^n = ln 9^2
n ln2 = 2 ln9
n = 2 ln9/ln2
2006-11-05 04:55:56 · answer #3 · answered by Dr. J. 6 · 0⤊ 0⤋
2^n = 9^2 = 81
so n ln 2 = ln 81
so n = ln 81/ln2 = 6.340
2006-11-05 04:53:03 · answer #4 · answered by grandpa 4 · 0⤊ 0⤋
just so you know ^ is a carrot it say that the number behnd is an exponent. 9^2 is nine to the power of two.
2006-11-05 04:52:05 · answer #5 · answered by -tima 3 · 0⤊ 0⤋
n log2 = 2 log9
n= 2 log9/log2
n= 6.34
2006-11-05 04:49:17 · answer #6 · answered by Anonymous · 0⤊ 0⤋
n= 2ln9/ln2
2006-11-05 04:48:22 · answer #7 · answered by J 6 · 0⤊ 0⤋
n*ln2=2ln9
n= 2ln9/ln2 and so on....
2006-11-05 04:46:26 · answer #8 · answered by Vladimir S 2 · 0⤊ 0⤋
oh my............... I dont have a clue.
2006-11-05 04:46:02 · answer #9 · answered by Help Me Help You 3 · 0⤊ 0⤋