if an engine must do 500 joules of work to pull a 10 kg load up to a height of 4 meters, what is the efficienc

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if an engine must do 500 joules of work to pull a 10 kg load up to a height of 4 meters, what is the efficienc

2006-11-05 04:32:15 · 2 answers · asked by laura k 1 in Science & Mathematics ➔ Physics

2 answers

10 kg load weight 98 Newtons (10 x 9.8).
A force of 98 newtons acting over a distance of 4 meters does 392 joules (= 4 x 98 newton-meters) of work.
If the engine does 500 joules of work, its efficiency (output/input) is 392 / 500 = .784, or 78.4%.

2006-11-05 04:59:39 · answer #1 · answered by actuator 5 · 0⤊ 0⤋

10 kg load weight 98 Newtons (10 x 9.8).

2006-11-05 05:03:52 · answer #2 · answered by J 6 · 0⤊ 0⤋