2006-11-05 04:30:43 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Did you forget some of the initial conditions?
2006-11-05 04:34:50 · answer #1 · answered by Chris J 6 · 2⤊ 0⤋
there are 2 components of tension come to a sort the two one among them in sin & cos alongside the horizontal we get sixty 8 cos 24 ( in east) 32cos48 ( in west) sixty 8 cos 24 - 32cos48 = 40.7088 N attitude between them is a hundred and eighty consequently the two one among them and you gets alongside east horizontal tension component. now come to a sort vertical components 32 Sin 40 8 (north) sixty 8 sin 24 (North) upload the two one among vertical components. sixty 8 sin 24 + 32 Sin 40 8 = fifty one.438 Now we've been given the two vertical and horizontal components upload the two utilising vector addition attitude between the two is ninety resultant tension = (fifty one.438 ^ 2 + 40.7088 ^ 2)^ a million/2 = sixty 5.597 MA = sixty 5.597 A = sixty 5.597/sixteen = 4.09 m/s/s tan theta = fifty one.438/ 40.7088 = a million.263 theta = fifty one.sixty 4 degree north of east
2016-11-27 20:17:43 · answer #2 · answered by ? 4 · 0⤊ 0⤋
ok ?
2006-11-05 04:33:21 · answer #3 · answered by Triathlete88 4 · 0⤊ 0⤋