Block B is initially at rest on block A, which is at rest on a smooth frictionless floor. There is friction between block A and block B. The coefficient of static friction between the blocks is 0.300 and the coefficient of kinetic friction between the blocks is 0.250. mA = 5.00 kg and mB = 3.00 kg. A horizontal force of F = 14.0 N is applied to block A. What is the magnitude of the frictional force on block B?
-if you could show what steps you used to get the answer, that would be great :)
2006-11-05 03:54:20 · 2 answers · asked by catherine p 1 in Science & Mathematics ➔ Physics
the friction force between A and B = mgk=3X9.8Xk where k=.3 or .25. When a force of 14 n is applied to A, a frictional force of (14/5)3 must be applied to B or it will move relative to A. so
3 * 9.8 * .3 = 8.82 is less than (14 / 5) * 3 = 8.4
B will slip so the answer is 3 * 9.8 * .25 = 7.35
2006-11-05 11:05:41 · answer #1 · answered by meg 7 · 1⤊ 0⤋
the magnitude of the frictional force on block B is 5.25 N.
2006-11-11 21:37:36 · answer #2 · answered by Galaxy D 2 · 0⤊ 0⤋