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TWO NUMBERS.BE SEREOUS PLZ. WANNA BE GENIUS HERE.

2006-11-05 02:25:12 · 6 answers · asked by kurudo_akabane 1 in Science & Mathematics Mathematics

6 answers

Tackling the problem bit-by-bit:

First, let x = the larger number
let y = the smaller number

You can write out an equation to show their relationship of "difference" by:
x - y = 68

Next, you write out the equation to show their quotient relationship by:
x/y = 5
which gives:
x = 5y

Now plug x = 5y into the "difference" equation:
(5y) - y = 68
which gives
4y = 68
which gives
y = 17

Now plug y = 17 into the "difference" equation:
x - 17 = 68
x = 85

2006-11-05 02:42:43 · answer #1 · answered by Carinna C 2 · 0 0

Let x and y be the two unknown numbers.

Given:
x - y = 68 ....(eq. 1)
x / y = 5 .....(eq.2)

For equation one:
x - y = 68
x = 68 + y

For equation two:
x / y = 5
x = 5y
But x = 68 + y
→
68 + y = 5y
68 = 5y - y
68 = 4y
68 / 4 = y
17 = y

Now substitute this back in one of the equations to calculate x.

x / y = 5
x / 17 = 5
x = 5 * 17
x = 85

Required numbers are: 17 and 85.

2006-11-05 02:44:42 · answer #2 · answered by Brenmore 5 · 0 0

A - B = 68
A/B = 5 => A = 5B

=> 5B - B =68 => B = 68/4 = 17
and A = 85

2006-11-05 02:40:17 · answer #3 · answered by Anonymous · 0 0

Let the two numbers be 'x' and 'y'.
y - x = 68.........Equation 1
y/x = 5.............Equation2
Two equations, two unknowns
y/x = 5
y = 5x
Now substitute in Equation 1
5x - x = 68
4x = 68
x = 68/4
x = 17
Now substitute the value of 'x' in Equation 2
y = 5x
= 5*17
= 85.
The two numbers are 85 and 17.

2006-11-05 02:53:12 · answer #4 · answered by Akilesh - Internet Undertaker 7 · 0 0

let the numbers be x and y
the equations
x-y=68
x/y=5=>x-5y=0
4y=68
y=17
x=68+17=85
the nos are 85 and 17

2006-11-05 02:32:21 · answer #5 · answered by raj 7 · 0 0

85 and 17.

2006-11-05 02:29:17 · answer #6 · answered by msrvnn 2 · 0 0

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