2006-11-04 22:20:44 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
hypotenuse^2= (3x)^2+x^2=9x^2+x^2= 9x^2+x^2=10x^2
hypotenuse= sqr(10) x
2006-11-04 22:26:44 · answer #1 · answered by fii 3 · 0⤊ 0⤋
u can use pythagoras' theorem, that is, in a right angle triangle, a^2+b^2 = c^2 , where a and b are the 2 sides of the triangle and c is the hypotenuse. so, for ur questions, (3x)^2 + x^2 = c^2. then, find c
2006-11-05 06:23:39 · answer #2 · answered by michael 2 · 0⤊ 0⤋
use the formula
Hypotenuse2= a2+ b2 ( a, b being the opposite sides of the hyp.)
so the hypotenuse will be (3x)2+ (x)2 that is square root of 10x2
2006-11-05 06:28:00 · answer #3 · answered by misty_illusionz 2 · 0⤊ 0⤋
(3x) square + x square = 9x square + x square = 10x square
(the hypotenuse) = square root (10) x
2006-11-05 07:39:16 · answer #4 · answered by Anonymous · 0⤊ 0⤋
ok...you know pytheg rule: a2+b2=c2?
c is hypotenuse so therefore:
[3x]2 + [x]2 = c2...............2 meaning squared
9x2 + x2 = c2
10x2 = c2
now take the square root of all:
c= square root of [10x2]
2006-11-05 06:29:53 · answer #5 · answered by dragon_89 1 · 0⤊ 0⤋
h² = 9x² + x²
h² = 10x²
h = x . sqr(10)
2006-11-05 06:24:11 · answer #6 · answered by just "JR" 7 · 0⤊ 0⤋
rt [(3x)^2+x^2]
rt[10x^2]
rt(10)x
2006-11-05 07:46:07 · answer #7 · answered by . 3 · 0⤊ 0⤋