What is the first differential of f(x)=(x-2)x(x+1.22)^2 ?

Answer 1

f(x)=(x^2-2x)(x^2+2.44x+1.4884)
=(x^4+2.44x^3+1.4884x^2-2x^3-4.88x^2- 2.9768x)
=(x^4 + 0.44x^3 - 3.3916x^2 - 2.9768x)

F(x)=(x^5)/5+(0.44x^4)/4-(3.3916x^3)/3- (2.9768x^2)/2+c

am i really asked a Q?

Answer 2

if u mean f(x)= (x-2)x(x+1.22)^2, den it is..

f'(x)= (x+x-2)(x+1.22)^2 + x(x-2).2(x+1.22)
= (2x-2)(x+1.22)^2 + (x+1.22)(2x^2 - 4x)
= (x+1.22) [ (2x-2)(x+1.22) + (2x^2-4x)]
= (x+1.22) ( 4x^2 + 8.44x -2.44)

voila!!!

Answer 3

f'(x)=(x-2)(x+1,22)^2+x(x+1.22)^2+2(x-2)x(x+1.22)(1)
f'(x)=(x-2)(x+1.22)^2+x(x+1.22)^2+2x(x-2)(x+1.22)
f'(x)=(x+1.22)((x-2)(x+1.22)+x(x+1.22)+2x(x-2))
f'(x)=(x+1.22)(x^2-2x+1.22x-2.44+x^2+1.22x+2x^2-4x)
f'(x)=(x+1.22)(4x^2-3.56x-2.44)
hope i'm not wrong.