If I drop two balls, 100&15 pounds, from 100mts of height at the same time which one is going to arrive first.

Question

If I drop two bowling balls of different weight ,lets say one of 100 pound and the other of 15 pounds,at exactly the same time from exactly the same height, which one arrives first to the ground?

Answer 1

both are the same if it is drop at the same height because the gravity speed is 10 ms-2 (9.81ms-2 more accurate)

Answer 2

If both of the balls are the same size and shape, then both will hit the ground at exactly the same time. The 100 lb ball will hit the ground with a much greater force, but at the same time as the 15 lb ball.
In my physics class we did an experiment by putting a feather and a nickel in a glass tube. We vacuumed all the air out the let them drop. They both hit the ground at the same time showing that, neglecting air resistance, the force of gravity is the same on everything.

Answer 3

As they are bowling balls they have to be a standard size, but there are limits to the accuracy with which they are made, one will be slightly bigger than the other and this will see higher drag from air resistance (at a given speed) than the smaller ball, it will also have more upthrust (assuming that the finger holes are the same size) than the smaller ball due to displacing a very slightly higher volume of air.

If the larger ball is also the less massive ball then it is clear that this ball will reach the ground later than the smaller and more massive ball, otherwise you have a really tricky piece of math. I'll use 40kg and 7 kg balls if you don't mind because I find all those slugs and foot-poundal seconds very confusing - sorry.

The force acting downwards on each ball is mass*g , the forces acting upward are bouyancy ( not proportional to mass but to volume) and drag (complex relationship to cross-sectional area, surface properties, shape and speed - not proportional to mass). The faster the ball goes the higher the drag, but it actually has to be going faster to experience higher drag and will therefore get to the bottom first, ignore the drag for now then and look at the bouyancy, assume that it is the same for both balls and = B newtons. Net force on the 40kg ball is 40*g-B , on the smaller is 7*g-B
acceleration is inversely proportional to mass
and (40g-B)/40 > (7g-B)/7 so the massier ball will accelerate faster and reach the ground first.

Answer 4

No they gained't opposite to medical theory: specific this is actual that something droped from any altitude will drop at 32 feet in line with 2d, in spite of the undeniable fact that there is a curve in acceleration that maximum persons forget! a fifteen pound bowling ball will attain that velocity until now a 8 pound bowling ball will. So if the two have been drop from a ten tale development or perchance a 50 tale development at precisely an identical 2d, the 15 pound ball will attain finished droping velocity until now the 8 pound ball will. and it will benefit a fractional ever so little benefit in incredibly time and hit the floor first!

Answer 5

Though people will say the experiment was done centuries ago by Galilio and both will fall togather; while saying so what they forget is the air resistance. Air resistance does not only depend on the surface area of the balls but also on their volume so thing we have to consider is the ratio of surface area to the volume. If both the balls are made of same maetrial and are perfectly spherial the ratio becomes 3/R where R is the radius of the circle. From this what can be concluded is the ratio will be larger for smaller sphere so it will experience a greater resistance of air so will fall slowly than the greater ball.

Answer 6

Both will reach at exactly the same time! When u drop them the initial velocity is 0m/s. Any body dropped from a certain height onto the ground accelerates at exactly same rate which is approximately equal to 9.8 m/s2. This is the acceleration due to gravity of the earth. So when they are dropped from exactly the same height, at exactly the same time, with exactly the same initial velocity, they will have the same acceleration and reach the ground at the same time. The time and final velocity depend on the above factors. In the question, all the above factors are equal. If the time is to be different, then we have only one option that the acceleration be different, which is not, since in vertical motion it is acceleration due to gravity that acts which doesn't depend on the mass of the object.
I will always be ready to give u the proof of why acceleration due to gravity does not depend on the mass of the object, if u need it in the future.

Answer 7

100lbs, although people would say the experiment with Galileo should show otherwise they are wrong. There is wind resistance. The bigger ball would suffer from less resistance because of its mass.

Now if you're dropping it on a mountain top, the 100 will fall first, but if you're dropping it from like 3 ft above the ground they will hit the ground at the same time because the wind resistance is insignificant.

Answer 8

All objects fall at the same rate, regardless of their weight. This may not be obvious if you drop a stone and a feather, but that is because the feather gets a push up from the air that is large enough to make it fall more slowly.

To understand this, it helps to know a little about inertia. Inertia is basically how hard it is to change the motion of an object. This is easily understood when you try to push two boxes. If one weighs 100 lbs, it will be difficult to push. If the other weighs 1 lb it will be easy to push. Since they have different weights, they also have different masses. The heavier, more massive, box has more inertia than the lighter, less massive, box.

When you drop two stones, gravity from the Earth pulls them towards its center. The Earth is pulling at each of these stones, trying to increase their speed. But, since they have mass, they also have inertia. The more massive stone has more inertia, and so it is harder to increase its speed. The less massive stone has less inertia and so it is easier to increase its speed. But, since the more massive stone is heavier, it is being pulled harder by the earth. Likewise, since the less massive stone is lighter it is not being pulled by the Earth as much. These things balance each other out so that they end up falling the same distance in the same time, and have the same speed the entire time.

Answer 9

Nobody knows for sure. It depends mainly on their size and shape. If there are finger holes in the bowling balls then several complex considerations are introduced by the orientation and spin rates and spin axes which are more conveniently neglected. Let's assume that the bowling balls don't have finger holes drilled out. Using Newtonian mechanics, if you mean bowling balls made of the same material, the 100 pound ball would encounter more drag than the 15 pound ball because it is larger. For the purposes of introductory physics, you would be obliged to discount the possibility of air resistance in your theoretical model, which would give the result that they arrive at exactly the same time. In real life, it's impossible to get a perfect vacuum, so the smaller one would arrive first. On a stochastic molecular scale, with a very low pressure, it's theoretically possible that the net upward kinetic energy (and thus the momentum) transferred during the drop to the smaller ball by the vapor particles would exceed the corresponding amount transferred to the larger ball due to random fluctuations, causing the larger ball to arrive first. The chance of this occurring, however, would be vanishingly small.
The same problems arise if a significant amount of turbulence or currents are allowed for in the partial vacuum, making this an intractable question. Leaving this consideration aside, suppose instead that the balls are the same size, and one is made of denser material than the other, but they are coated with a layer of the same material and texture on the outside, resulting in identical drag. Now, even if we switch to Einsteinian relativistic mechanics, we get the same result as Newton did when he first proposed the law of universal gravitation. Let's conveniently avoid discussion of whether simultaneity occurs, and whether time flows continuously, and assume that it can be established precisely which one is first to arrive.
Even with a near-vacuum (such as in deep space) there is an additional factor of the slight pressure of electromagnetic radiation on the bowling balls which would result in a differential average speed over the length of the drop (which might require a long time in deep space, especially if the experiment is conducted from the surface of a small body such as an asteroid.)
Aside from all of these considerations, the recently discovered existence of neutrino mass can introduce yet smaller deviations which would also be unpredictable because of the unknown cause of their interaction with the matter in the bowling ball. If the neutrinos oscillate from high-interaction to low-interaction states and back again, there is no telling which ball will arrive first until scientists are able to precisely measure the neutrino flux through a given volume of space. The equipment necessary to determine the answer simply is not available at this point in history. Perhaps you will be one of those that invent or develop such equipment. Another factor is the obsolescence of the Standard Model of particle physics which leaves us with an indeterminate answer due to the unknown speed of propagation of gravitons (if their existence or nonexistence can in fact be demonstrated, and if the strength, intensity, and frequency of interstellar gravitational waves can be predicted, measured, and their effects anticipated prior to dropping the bowling balls. Many physicists believe these effects may not be subject to conventional analysis at all, and if the microeffects of gravity (and/or antigravity, if antigravity is real--don't forget the possibility of magnetic monopoles or dipoles partially levitating one or other of the bowling balls, depending on their composition and radial density distributions--unless you want to introduce a constraint of spherical uniformity) are derived from quantum-type subatomic changes, the uncertainty principle could ultimately prove that there is *no* definitive answer to this question that can be arrived at until the dropping times themselves are actually measured. This would mean that it is categorically impossible to state the answer without information that is not available until *after* the conclusion of the experiment being performed. Stated another way, intercept a particle (or particles) traveling backward in time from after the bowling balls arrive at the ground, that has been influenced by both of them (through entwining, etc. of their paths through negative spacetime) and decode the result, in violation of causality, if you really want to know. Of course, if you can do that, there are more interesting experiments that you can also do which have much greater significance--but you will have to cross that bridge when you come to it--unless you can find a way to cross it before you arrive at it. Essentially then, so far as is known, there is no completely accurate answer to your question, only a series of approximate answers, some of which are usually close enough. This is the usual state of things in experimental science.

Answer 10

if both the balls are dropped in vaccum then both the balls reach the ground at the same time.if both feather and stone are dropped in vaccum then both will reach the ground at the same time.
but in natural conditon there will be air friction.so whichever has lower surce or lower air friction reaches the ground faster.