how many atoms of eache of the following elemnts would be present in samples having the following mass?
1)14.01g of nitrogen atoms
2)40.08g of calcium atoms
why??
2006-11-04 18:11:03 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The atomic mass of nitrogen is 14.00674 grams/mole and the atomic mass of calcium is 40.078 grams/mole. At a level of accuracy of four significant figures, the masses you have been given correspond to the mass of one mole of each of these elements. Therefore, there is one mole of nitrogen atoms in 14.01 gms of N and one mole of calcium atoms in 40.08 gms of Ca.
One mole of atoms = 6.022 * 10^23 atoms.
2006-11-04 18:37:00 · answer #1 · answered by hfshaw 7 · 0⤊ 0⤋
1) the moles of nitrogen 14.01/14.01 = 1 mol
2) the moles of calcium 40.08/40.08 = 1 mol
the number of atoms = Avogadro number * number of moles
n = N_A (A here means Avogadro) * 1 = 6.02*10^23 atoms
2006-11-04 18:43:50 · answer #2 · answered by James Chan 4 · 0⤊ 0⤋
Its called Avogadros number 6.022x10e23 atoms per mole of a compound/element. multiply # of moles by above = # of atoms. But don't forget to convert from grams to moles atomic weight = # of grams in a mole of an element
2006-11-04 18:38:56 · answer #3 · answered by thewizardofodd 3 · 0⤊ 0⤋
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2016-10-15 09:43:22 · answer #4 · answered by raffone 4 · 0⤊ 0⤋