the sides of a right - anglrd triangles are 21cm, 28cm; find the length of the perpendiculars drawn to the hypotenuse from the right angle?
#plze put ur mouze poitr over the ques. to see full ques
2006-11-04 17:36:35 · 5 answers · asked by frank castle 1 in Science & Mathematics ➔ Mathematics
Is this your 1,000,00th question? If you don't do your own homework you won't learn anything
2006-11-04 17:43:16 · answer #1 · answered by econdrone 2 · 0⤊ 0⤋
i know that first you have to find the length of the hypotenuse using the formula
a^2+b^2=c^2
(21)^2+(28)^2=c^2
441+784=1225
c= sq root of 1225
c=35
the length of the hypotenuse is 35 cm
sorry i dont remember the rest
2006-11-04 17:50:11 · answer #2 · answered by tma 6 · 0⤊ 0⤋
this is a very simple question.
first of all we have to find the length of hypotenuse=21sq.+28sq. under the root
=35.
now draw the perpendicular to the hypotenuse and let it be y
let the distance from pt p to pt of line of length 28 be x.
the remaining distance=35-x
now, xSq+28sq=ysq (1)
(35-x)sq+21sq=ysq(2)
from 1 & 2
xsq+784=(35-x)sq=441
on olving these eqn we get that
x=12.6
so,ysq.=(12.6)sq+784
y =(158.76+784)sq.root
y =30.7043
2006-11-04 19:23:16 · answer #3 · answered by cool boy 1 · 0⤊ 0⤋
a^2+b^2=c^2
a : b : c = 3 : 4 : 5
7(3) =21
7(4) =28
7(5)=35
so c=35
2006-11-04 18:05:23 · answer #4 · answered by safrodin 3 · 0⤊ 0⤋
i have an advice,....
just do your own homework!!!
2006-11-04 17:58:22 · answer #5 · answered by katenz_25 1 · 0⤊ 0⤋