math help in algebra 2?

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2006-11-04 17:26:36 · 4 answers · asked by Carpe Diem 1 in Science & Mathematics ➔ Mathematics

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:>peace

2006-11-10 17:18:14 · answer #1 · answered by Anonymous · 0⤊ 0⤋

Do you want to simplify it or something?

(x+y)/(x-y)/(1/x-1/y)

(x-y)(1/x-1/y)/(x-y)

(x/y+y/x)/(x-y)

(x^2+y^2)/(x-y)

Have fun with that.

2006-11-05 01:33:11 · answer #2 · answered by econdrone 2 · 0⤊ 0⤋

The whole thing would simplify to (x+y)/(x-y)*xy/(y-x)

2006-11-05 01:33:09 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋

we have :
[(x+y)/(x-y)] / [1/x - 1/y ] =[ (x+y)/(x-y) ] / [ (y-x) / xy ]
= - [ (x+y)/(x-y) ] / [ (x-y)/xy ] = - [xy(x+y)]/(x-y)^2

2006-11-05 02:15:13 · answer #4 · answered by James Chan 4 · 0⤊ 0⤋