2006-11-04 16:55:41 · 11 answers · asked by sunny 1 in Science & Mathematics ➔ Chemistry
Dr J your equation doesn' t balance.
I would write an ionic equation to show NaOH dissolving in H2O.
NaOH (s) ------> Na+(aq) + OH- (aq)
2006-11-04 22:21:53 · answer #1 · answered by Anonymous · 0⤊ 0⤋
NaOH will dissolve in the water
2006-11-06 14:27:56 · answer #2 · answered by latif_1950 3 · 0⤊ 0⤋
NaOH + Water ===> NaOH (aqueous)
2006-11-05 12:54:41 · answer #3 · answered by Anonymous · 0⤊ 0⤋
NaOH + water = weaker NaOH
The NaOH should be added to the water slowly as it may heat up.
2006-11-05 01:08:42 · answer #4 · answered by Norrie 7 · 0⤊ 1⤋
NaOH will ionize to Na+ and OH- and water molecules will surround each ion.
2006-11-05 01:00:06 · answer #5 · answered by smarties 6 · 1⤊ 0⤋
The water is not actually written in the equation as there is no 'reaction' with it.
NaOH(s) = Na+(aq) + OH-(aq)
There is quite a lot of heat given off as well.
2006-11-05 13:43:49 · answer #6 · answered by Examiner 3 · 0⤊ 0⤋
Sodium Ion(Na+) and Hydroxide Ion(OH-)
when Sodium hydroxide solves in water, it ionizes into this two ions. water in only a solvent.
2006-11-05 01:01:29 · answer #7 · answered by CH4 3 · 0⤊ 0⤋
That will result in an aqueous solution of sodium hydroxide.
2006-11-05 01:03:41 · answer #8 · answered by Steven B 6 · 1⤊ 0⤋
I think the product of NaOH + H2O --> H2O +Na2O
But your not done....you have to balance the equation thus getting:
2NaOH + H2O --> 2H2O +Na2O
How this helps..... :-)
2006-11-05 01:10:11 · answer #9 · answered by Aug 1 · 1⤊ 2⤋
NaOH + H2O ---> Na+(aq) + OH-(aq)
2006-11-05 01:03:03 · answer #10 · answered by Dr. J. 6 · 2⤊ 1⤋