give the equation for the circle with center C(3, -2) and radius 4.
2006-11-04 16:28:49 · 8 answers · asked by cil 1 in Science & Mathematics ➔ Mathematics
(x - 3)^2 + (y + 2)^2 = 16
if the center is (h,k) and the raduis is r, the equation is
(x - h)^2 + (y - k)^2 = r^2
2006-11-04 16:30:27 · answer #1 · answered by greeiore 3 · 0⤊ 0⤋
2 2
X Y
___ + ____ = 16
9 4
2006-11-05 00:35:00 · answer #2 · answered by goodcharacter 3 · 0⤊ 0⤋
(x-3)^2 + (y+2)^2 = 16
2006-11-05 00:30:18 · answer #3 · answered by z_o_r_r_o 6 · 1⤊ 0⤋
(x-3^2+(y+2)^2=16
2006-11-05 00:30:38 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
(x - 3)^2 + (y + 2)^2 = 16
or maybe
(x - h)^2 + (y - k)^2 = r^2
if the center is (h,k) and the raduis is r.
Do Not Stress Out and Good Luck!
You may also want to ask your teacher or professor to go back over this with you so that you will know this for the test.
2006-11-05 01:11:04 · answer #5 · answered by millie_milla 2 · 0⤊ 1⤋
The formula is (x-h)^2 + (y-k)^2 = r^2
where h is x coordinate of the center
and k is y corrdinate of the center
and r is radius.
so...
(x-3)^2 + (y+2)^2 = 16
2006-11-05 00:31:56 · answer #6 · answered by tkquestion 7 · 0⤊ 0⤋
(x-3)^2 + (y+2)^2 = 16
come on :)
2006-11-05 00:31:44 · answer #7 · answered by Anonymous · 0⤊ 0⤋
why are you asking this on saturday night...
you are supposed to wait until Sunday night
2006-11-05 00:38:06 · answer #8 · answered by Anonymous · 0⤊ 0⤋