Let there be a right-angled triangle.
now,
we know that,
(2n^2+2n+1)^2=4n^4 + 4n^2 + 1 + 2(4n^3 + 2n+ 2n^2)
=>(2n^2+2n+1)^2=4n^4 + 4n^2 + 1 + 8n^3 + 4n+ 4n^2
=>(2n^2+2n+1)^2=(4n^4 + 4n^2 + 8n^3) + (1 + 4n+ 4n^2)
=>(2n^2+2n+1)^2=(2n^2 + 2n)^2 + (2n+1)^2
This gives solutions
(3,4,5); (5,12,13); (7,24,25); (9,40,41)........................
the above relation is true for all n belonging to natural numbers
this way you can find solution for any pair of sides the 3rd side been given.
put the given side equal to one in equation and find positive n by solving the quadratic and find all the sides.
Eg:If hyputenuse is given as 5
Solve 2n^2 + 2n + 1= 5
=>n=1 therefore other sides are 3 and 4
Choose this as best, if correct.
2006-11-05 01:49:10
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answer #1
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answered by Anonymous
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There are tables of Pythagorean triplets. You can match up your hypoteneus with the corresponding triplet.
See the source below for a list of the triplets up to a hypoteneus length of 100.
2006-11-05 00:16:30
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answer #2
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answered by Ted 4
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with a right triangle, you can not find the lengths of the sides just by knowing the hypotenuse. you would need to know an angle (other than the 90)
2006-11-04 23:56:55
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answer #3
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answered by yourdaddy0 2
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You can not solve a triangle with 2 pieces of information.
2006-11-05 00:14:32
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answer #4
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answered by Dr. J. 6
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Hello Rajesh
Do you mean primitive triplets or just any triplet ?
For primitive triplets you can find unique solution.
Here is the formula for your triplets
(a,b,c)=(2m,m^2-1,m^2+1).
Are you tiling your kitchen floor ;)
2006-11-05 00:33:56
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answer #5
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answered by ramesh the great 1
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you need to know the one more side. however, if you are talking about an isoscles right triangle, you can figure out the other two sides.
2006-11-05 00:04:05
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answer #6
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answered by Aaron 3
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you can find it out if you can construct the triangle with mathematical conscience a pencil a passer and a lineal.
2006-11-05 00:18:02
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answer #7
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answered by gjmb1960 7
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