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2 people playe don a friday chess tournment. they each play seven games, they clam that they each won the same number of games, is this possible with no draw. if so explain

2006-11-04 13:28:07 · 9 answers · asked by Ernando 4 in Education & Reference Homework Help

9 answers

Probably they are mentally retarded.....
Are they from Mental Hospital???

2006-11-04 13:30:47 · answer #1 · answered by bugi 6 · 1 1

Uhhh... only if they're still playing the seventh game. In that case, they'd each have three wins, and no winner yet for the seventh, so it's not a draw, a win, or a loss.

2006-11-04 13:32:59 · answer #2 · answered by Anonymous · 0 0

They didn't play all the games against each other. Some were against other people.

2006-11-04 13:34:08 · answer #3 · answered by hayharbr 7 · 1 0

Newcastle is my community group as I reported so i like to verify them do properly,for sure i do no longer help them yet different than for Chelsea i like to verify them win each a possibility pastime. one subject nonetheless,the great communities play a weakned group interior the League cup it became Newcastle adolescents vs Chelsea adolescents truly,yet Newcastle have a stable adolescents group. Yeah you do many times draw with us for some reason...particularly a stable group,Newcastle.greater desirable than the macems

2016-10-03 07:07:26 · answer #4 · answered by ? 4 · 0 0

THEY EACH PLAYED SEVEN GAMES.

Where's the AGAINST EACH OTHER?

It is not necessary that they played against each other.

2006-11-04 14:19:36 · answer #5 · answered by Cat Fanatic 2 · 0 0

Not that I know of, there have to be one draw

2006-11-04 13:30:56 · answer #6 · answered by Pro-Star 2 · 0 0

Sure -- they didn't play against each other.

2006-11-04 13:38:50 · answer #7 · answered by Anonymous · 1 0

they weren't there on the day of the last game.

2006-11-04 13:34:03 · answer #8 · answered by Anonymous · 0 0

they don't have play each other

2006-11-04 13:43:21 · answer #9 · answered by alan21627 4 · 0 1

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