How do I do this word problem?

Question

A rectangle has an area of 36 square meters. If the legth is 5 meters longer than the width , what is the perimeter?

Answer 1

l = 5+w

l*w = 36

p = 2l + 2w

Answer 2

Let the length be 'x+5' and the width, 'x'
(x + 5)x = 36
x^2 + 5x = 36
x^2 + 5x - 36
x^2 + 9x - 4x - 36 = 0
x(x + 9) -4(x + 9) = 0
(x - 4)(x + 9) = 0
Either x-4 =0, or x+9 = 0
Put x + 9= 0
x = -9
This is not possible because, if x = -9, perimeter will turn out to be negative.
Put x -4 =0
x= 4
Breadth = 4m
Length = 9m
Perimeter = 2(4 + 9)
= 2*13
= 26 m

Answer 3

Let width = x m
then, length = (x + 5) m
Area = length x width = 36
= x (x + 5) = 4 x 9
x = 4
w = 4 m
l = 9 m
Perimeter = 2 ( l + w)
= 2 (9 + 4)
=2 x 13
=26 m

Answer 4

Area= 36
l xb =36

assume b= x
thus , l= x+5

Area = (x+5)x(x)
x2+5x = 36
on solving x=4, -9
since length cant be negative x= 4

thus breadth = 4, length = 4+5=9

Perimeter = 2(l+b)
= 2(4+9)= 26

Answer 5

You have to do it in 2 steps.
First find the length of the to sides.
Call the short side X and then the long side is X+5
X(X+5) = 36
X^2 + 5X = 36
X^2 + 5X - 36 = 0
Factor that to:
(X+9)(X-4) = 0 Therefor
X = 4
X = -9
One side is 4 and the other side is 4+5 or 9

Perimiter is 2(L+W)
2(4+9) or 26

Answer 6

the problem states that the area is 36 m^2.
the problem also states that L = 5+W

the equation to find the area is A = L x W
If you replace L with 5+W, then you get...

A = (5+W) + W

You know the area, solve for W.

Now that you know the L and W, the perimeter will be 2L + 2W

Answer 7

let x=width, then l=x+5 so
A=36=x(x+5)
x^2+5x-36=0
(x+9)(x-4)=0
x=-9 not physically possible
x=4
so the rectangle measures 4*9=36m^2
the perimeter=2*4+2*9=8+18=26m

Answer 8

p = 2l + 2w