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Please SHOW WORK!!!!!!!!!!!!! PLEASE

2006-11-04 09:09:19 · 14 answers · asked by Anonymous in Science & Mathematics Mathematics

14 answers

I suppose its in an monogamous society =>
1/3*X=3/5*Y <=>
X=9/5*Y

the total amount of people will therefor be
X+Y=Y(1+9/5)=Y*14/5

the amount of people married is
2*1/3*x=2*3/5*Y because amount of women and men is equal and the total amount must be the twice of one of a married sex

now we can calculate the fraction of married people in town

Fraction of M-people=(2*3/5*Y)/(Y*14/5)=
6/14=3/7
=======

2006-11-04 09:42:50 · answer #1 · answered by Broden 4 · 0 1

1/3 + 3/5 = 14/15

2006-11-04 17:15:32 · answer #2 · answered by pkababa 4 · 0 2

I shall start by assuming they are monogamous.

1/3 of men = 3/5 of women (as an actual number)

Let y be the number of married couples.

1/3 of men = y

So,Total number of men is 3y (multiply by 3 and divide by 1)

Similarly 3/5 of the women = y

Total number of women is 5y/3 ( multiply by 5 and divide by 3)

Total number of people in the town is 3y + 5y/3

Put these numbers over a common denominator ("make bottom line the same")

total number of people in town is (9y + 5y)/3

14y/3

The total number of marrieds is y men + y women = 2y people

Now make a fraction of the number of marrieds divided by the total number of people in town

2y divided by 14y/3

=2y x 3/14y

=6y/14y

(the Y's can be "cancelled" if you use that expression - if not, divide both numerator and denominator ("top and bottom") by y

= 6/14

= 3/7

2006-11-04 18:28:44 · answer #3 · answered by rosie recipe 7 · 0 1

1/3 + 3/5
Find Lowest Common Denomonator
Which is 15
1/3 mltiply the top and the bottom by 5 so
5/15

3/5 Multiply the top and the bottom by 3 so 9/15

Add 9/15+ 5/15= 14/15 of people are married

2006-11-04 17:13:55 · answer #4 · answered by Hilary 1 · 1 3

1/3=5/15 and 3/5=9/15 (eqivalent fractions)

so... lets say the town has 30 people in it.

so statistically half are men and half are women.

15 men, 15 women... so there are 20/15 people married.

2006-11-04 17:18:44 · answer #5 · answered by benatmur 2 · 0 2

the question is incomplete. we do not know how many children live in this town, and the question is how many PEOPLE are married. this does include children

but the answer to the question is actually

there are 105 women
189 men
63 men married
63 women married

126/294 people are married
3/7

2006-11-04 17:25:01 · answer #6 · answered by iberius 4 · 0 2

P = # of people
W = # of women
M = # of men
C = # married couples

P = W + M
C = W*(3/5) = M (1/3)
therefore W = M * (5/9)
C/P = M *(1/3) ./ [M (1 + 5/9) ]
therefore C/P = (1/3) / (14/9) = 3/14

2006-11-04 17:15:51 · answer #7 · answered by AnswerMan 4 · 0 2

m = number of men
w = number of women

ratio of married people : all people
m/3 + (3/5)w : m + w

number of married m = number of married w
(m/3) = w(3/5)
5m = 9w
m = (9/5)w

ratio of married people : all people
(9/5)w/3 +(3/5)w : (9/5)w + w
(6/5)w : (14/5)w
3:7

3/7

2006-11-04 19:41:42 · answer #8 · answered by paladin 1 · 0 1

let x=# of men, y=# of women
(1/3)x=(3/5)y
5x=9y
x=1.8y
total population =x+y=2.8y
(1/3)*1.8y+(3/5)y are married
.6y+.6y=1.2y are married.
122y/2.8y=12/28=3/7 of the people are married.

2006-11-04 17:16:47 · answer #9 · answered by yupchagee 7 · 0 2

number of men = x
number of women = y

men married = x/3
women married = 3y/5

fraction people married = x/3 + 3y/5

2006-11-04 17:17:14 · answer #10 · answered by toasteddeer 2 · 0 2

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