multiply and simplify?

Question

I have such a hard time writing this: please bear with me..


(x^2 + 4x + 3 / x^2 - 4x + 3) (x-3 / 3x+3)

I think I have it right..
How to multiply and simplify
help...

Answer 1

I also have difficulty typing this thypes of math problems. First, simplify the ax^2+bx+c parts in the first half to (x+c)(x+c) looking things first. So...

[(x-3)(x-1)]} is the first part. With the bottom of the second half, divide by 3, so that you get 3(x+1). Now line everything up like so...

(x+1)(x+3)(x-3)
_____________
3(x-3)(x-1)(x+1)

Now do the cancellations and you get the right answer...
(x+3)
____
3

Sorry for not working to convention, but it was easier to type it that way.

Answer 2

Well first lets take thisone step at a time, lets deal with the first quantity of (x^2 + 4x + 3 / x^2 - 4x + 3) , x^2 + 4x + 3 can be factored into (x+1)(x+3), and x^2 - 4x + 3 can be factored into (x-1)(x-3). The second quatity is (x-3 / 3x+3), and get be simplified like this (x-3/3(x+1)) The only difference is that you factored the 3 out of the denominator. So the problem looks like this now
((x+1)(x+3))/(x-1)(x-3)) multiplied with ((x-3/3(x+1)), now when you multiply it looks like this Numerator ((x+1)(x+3)(x-3)) diveded by denominator (x-1)(x-3)3(x+1). Now we can can simplify, by crosing out like terms. (X-3)(X+1) cancel out becaue they are both in the numerator and denominator. So you are left with (x+3)/3(x-1), cannot be factored anymore, so that is the answer.

Answer 3

1. (x^2 + 4x + 3) = (x + 1)(x+3) and ( x^2 - 4x + 3) = (x -1)(x-3)
Hence it becomes (x + 1)(x+3) / (x -1)(x-3)

2. (x-3 / 3x+3) = (x-3) / 3(x+1)

3. When you multiply 1. with 2. , you can cancel out (x+1) and (x-3), leaving you with an answer of (1 / 3) [(x+3) / (x-1)] = (x+3) / (3x - 3).

If you don't see it like this, try writing it out on paper so that you can see the actualy fractions. it helps when you are trying to cancel out the numbers. i hope this helps~!

Answer 4

Do you have enough parentheses in this?

Did you mean to write: (x^2 + 4x + 3)/(x^2 - 4x + 3) (x-3)/(3x+3)

If so, then factor out the first quotient:

((x + 3)(x + 1))/((x - 3)(x - 1)

Then factor out the 3 in the very last part:

3(x + 1)

Now cancel out your common factors on top and bottom, and you have your answer:

(x + 3) / (3(x - 1))

Answer 5

x+3/3(x-1)

Answer 6

First distribute 7(2 - x) which then will become 14 - 7x. Then upload 14 - 7x to 3x which will become 14 - 4x. Then distribute -4 to fourteen - 4x which will become -fifty six + 16x. Then remedy x - fifty six + 16x which will become 17x - fifty six. Then distribute 2 to 17x - fifty six which will become 34x - 112. Then upload 5 to 34x -112 which will become 34x - 107. very final answer is 34x - 107. Sorry no count if that's incorrect, yet I graduated from the proper college in S. Korea (Seoul U.) and had rapidly A's so i'm quite specific it somewhat is right.

Answer 7

Factor each numerator and denominator completely, then divide out common factors.

(x+3)(x+1)/(x-3)(x-1) times (x-3)/3(x+1)

(x+3)/3(x-1)