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3 answers

find what?...the dimensions of the box with the most volume?

Area = w^2 + 4wh = 1100 cm^2
h = (1100 - w^2 ) / 4w

Volume = h w^2 =
V = w^2 * (1100 - w^2 ) / 4w
V = w (1100 - w^2 ) / 4
V = 275w - (w^3)/4
dV/dw = 275 - (3/4)w^2
let dV/dw = 0
(3/4)w^2 = 275

w = 19.15 cm
h = 9.57 cm

2006-11-04 08:00:33 · answer #1 · answered by Anonymous · 0 0

Find what? Do the sides have to be squares, too? Then a topless box has five faces, and if each edge has a length of s, you just need to solve 5s^2 = 1100 if what you're trying to find is the length of the edge of the largest box you can construct.

2006-11-04 15:58:24 · answer #2 · answered by DavidK93 7 · 0 0

hmmm..
assuming that ALL 1100 sqcm is used, so the material given is in the shape of the Red Cross.
'''''_
'_|_|_
|_|_|_|
''''|_|

let the side of the base be x, and ht be y
4xy + x^2 = 1100 = 4 x 11 x 25
so the only possibility for x is 5, and so y = 11/5 = 2.2cm

Hope this helps=)

2006-11-04 16:05:34 · answer #3 · answered by luv_phy 3 · 0 1

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