You are part of a search-and-rescue mission that has been called out to look for a lost explorer. You've found the missing explorer, but you're separated from him by a 200 m high cliff and a 30 m wide raging river. To save his life, you need to get a 4.4 kg package of emergency supplies across the river. Unfortunately, you can't throw the package hard enough to make it across. Fortunately, you happen to have a 1.8 kg rocket intended for launching flares. Improvising quickly, you attach a sharpened stick to the front of the rocket, so that is will impale itself into the package of supplies, then fire the rocket at ground level toward the supplies. What minimum speed must the rocket have just before impact in order to save the explorer's life?
I know the rocket needs to travel 202.237 m (the hypotenuse of the triangle). So d=202.237. I am lost however, where to go from there.
Any ideas?
Thanks
2006-11-04
05:36:59
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3 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Physics
"The rocket travels in a parabolic trajectory (we assume it has a zero burn duration). It is at the peak with 0 vertical velocity when it lands on the cliff edge at s=200 m height. Under 1g deceleration, it takes SQRT(2*s/g) = 6.387 sec to reach this height. The horizontal distance traveled is 30 m in 6.387 sec for a velocity of 4.607 m/sec.
I hope you realize that when you impaled the package with the rocket, all the blood plasma, propane and brandy were lost."
That does not appear to be right, any other thoughts?
Thank you very much.
2006-11-05
08:59:04 ·
update #1
Sorry, the problem was that the rocket travels from the top of the cliff to the ground below where the explorer is. That is why the value you provided was incorrect.
2006-11-07
00:45:53 ·
update #2