how to graph a function of sorts y = sqroot (1-x^2)?

Answer 1

y^2 = 1 - x^2

y^2 + x^2 = 1

remember that a circle centered on (x=0,y=0) has the property

x^2+y^2 = r^2

where r is the radius

So your plot is simply a circle arc with radius 1 centered on the origin.

Answer 2

First you should establish the domain and range of the function: since 1-x^2 must be greater than zero (because we can't take the square of a negative number without resorting to the imaginary realm), x^2 must be <1, so -1
No notice that you can square both sides and rewrite the equation as:

y^2 +x^2 = 1, for 0
This is the definition of the unit circle who's radius is one and center at (0,0) (Plot it if you need to see it). And since y is restricted to 0
Gary H

Answer 3

Tabulate some values of x and y !

Answer 4

see the best online plotter:
http://www.teachers.ash.org.au/mikemath/calculators.html