∫(1/x)( ln x) dx =?

Question

(3/2)(ln x)^2 + C ?

(1/2)(ln x)^2 + C ?

- 1/(ln x) + C

ln |ln x| + C

Answer 1

*integrate* (1/x) (lnx) dx --use the substitution rule--
u = lnx
du = (1/x) dx
dx = x * du
*integrate* (1/x)(u) x*du --the two x variables cancel out--
*integrate* u du
[((u^2)/2) + c] = (((lnx)^2)/2) + c

Answer 2

Multiple =xc87 (764098)xzQ7 OK