4 ∫[g(x)] g'(x) dx =?

0 ⤊

4 ∫[g(x)] g'(x) dx =?

[g(x)]^2 + C

2[g(x)]^3 + C

ln |g(x)| + C

2[g(x)]^2 g'(x) + C

2006-11-04 05:12:12 · 3 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics

3 answers

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4 ∫[g(x)] g'(x) dx = 4 x 1/2g(x)² +c = 2g(x)²+c

its the first suggestion that u made but i think you forgot the number 4...

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2006-11-04 05:19:47 · answer #1 · answered by Anonymous · 0⤊ 0⤋

=[k(09)+7% [54]-[76]+C=789564B XXCB=23[32] -[56]=897675439tel.014563789654 OK

2006-11-04 13:18:44 · answer #2 · answered by MUTANT 2 · 0⤊ 0⤋

Where did c come from all of a sudden?

Have you missed out part of the question?

2006-11-04 13:20:27 · answer #3 · answered by Mark T 6 · 0⤊ 0⤋