yea
2006-11-04 03:47:37 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
With sides a, b, and c, a+b>c, a+c>b, and b+c>a.
2006-11-04 03:49:08 · answer #1 · answered by er_i_m 4 · 0⤊ 0⤋
If the three line segments have lengths of a, b, and c, respectively, then they can form a triangle if and only if the following three conditions exist:
a+b>c
a+c>b
b+c>a
For example, if the three lengths ar 3, 4, and 8, then a triangle is impossible because 3+4 is not >8.
2006-11-04 03:59:14 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
You can form a triangle if and only if the lengths of the two shorter segments total to more than the length of the other segment.
2006-11-04 03:52:21 · answer #3 · answered by Sangmo 5 · 1⤊ 0⤋
take the three line segments and label them as a, b, and c... now plug them into the equation: perspective C = cos^-a million*(a^2 + b^2 - c^2)/(2*a*b) this provides you with an perspective do the comparable element for each and all of the perimeters perspective B = cos^-a million*(a^2 + c^2 - b^2)/(2*a*c) perspective A = cos^-a million*(b^2 + c^2 - a^2)/(2*b*c) if each and all of the angles upload as much as one hundred eighty tiers, then the segments make a triangle...in the event that they do no longer, or your solutions to any of those equations would not artwork, then it incredibly is not any longer a triangle
2016-10-21 06:17:08 · answer #4 · answered by Erika 4 · 0⤊ 0⤋
by checking this rule:
the sum of lengths of any sides must b greater than the other side.
2006-11-04 03:50:07 · answer #5 · answered by mike 1 · 0⤊ 0⤋
If all the sides are shorter than the other two added up, then you're okay.
2006-11-04 03:51:35 · answer #6 · answered by Anonymous · 0⤊ 0⤋