2/pi
(ln 2)/3
6/5
3/2
0
1
2006-11-04 03:02:28 · 5 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics
The average value formula in the interval (a,b) is
AV = 1/(b-a) * DEFINT f(x) {evaluated from a to b}
AV = 1/(b-a) * {INT f(4) - INT f(-4)}
The integral will be 1/2(x^4 - 5x^2). If you evaluate this at x=4 and then at x=-4 and do the math it will be 0.
So the answer is 0.
2006-11-04 03:21:54 · answer #1 · answered by Dr. J. 6 · 0⤊ 0⤋
1
2006-11-04 03:08:38 · answer #2 · answered by Vladimir S 2 · 0⤊ 1⤋
The average value is 1/8 integral of 2x^3-5x from -4 to 4
(1/2)x^4-(5/2)x^2
So it will be 0
2006-11-04 03:22:22 · answer #3 · answered by munkmunk17 2 · 0⤊ 0⤋
average = [s(a+h)-s(a)]/h
[-4, 4] a=-4, (a+h) = 4 , h=8
f(x) = 2x^3 - 5x
{2(4)^3-5(4)-[(2(-4)^3-5(-4)]} / 8=27
@@...it's not on your answer list...
2006-11-04 03:20:51 · answer #4 · answered by Jason Chuan-Der S 2 · 0⤊ 1⤋
0 (zero)
2006-11-04 03:13:39 · answer #5 · answered by BotaXupeR 3 · 0⤊ 0⤋