The slope of the tangent line to y = x^3 - x where x = 1 is...? Can anyone figure this out?

2 ⤊

2 ?

-2 ?

-1/2 ?

2006-11-04 02:51:52 · 3 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics

Step 1: find y '
Step 2: fill in x=1
That gives the right answer 2

Th

2006-11-04 03:40:15 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋

2006-11-04 10:55:58 · answer #2 · answered by Vladimir S 2 · 1⤊ 1⤋

First, derivate the equation x^3 - x

you will get:

3x^2 - 1

Then substitute x with 1

3*(1)^2 - 1

=> 3*1 - 1
=> 2

So the answer is 2

2006-11-04 10:57:05 · answer #3 · answered by BotaXupeR 3 · 1⤊ 0⤋