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2006-11-03 22:21:13 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

subtance is Dark red wine.

2006-11-04 05:23:07 · update #1

substance is dark red wine.

2006-11-04 05:24:21 · update #2

4 answers

Insufficient information to compute.


Doug

2006-11-03 23:45:04 · answer #1 · answered by doug_donaghue 7 · 0 0

It depends on what substance it is and the amount of liquid it is in. Moles are based upon the number of grams of the substance per 6.02 x 10^23 molecules of it. Molarity is based upon the number of moles per liter of solution it is in.

The mM will therefore depend on the substance because 40 mg of sodium is a larger number of moles than 40 mg of sodium chloride.

The way to figure out your final answer is as follows:

(First, since you are in the "milli" scale, g/mole (the molecular weight of the substance) is equal to mg/millimole, so you can use that to simplify the math.)

So you take 40 mg and divide by the molecular weight of the substance (in mg/mmole) to give you the number of mmole of substance you have.

You then take the number of mmole and divide by the volume of solvent in liters, and you will get a mM answer. mM times 1000 gives you micromolar.

Hope that helped and was clear. I don't know how much background in the subject you have.

***EDIT: because "dark red wine" does not have a specific molecular structure (it is likely a mixture of several different molecules), and hence no molecular weight, it is not possible to calculate the molarity of the liquid. Density, however, is able to be calulated if you divide the weight (I don't know where you got 40 mg from...) by the volume (this would give you mg/L. Density is calculated in g/mL, so divide by 1000 to give you your answer)***

2006-11-04 06:40:57 · answer #2 · answered by shortstuf_2 3 · 0 0

That depends entirely upon what you have 40 milligrams of.

2006-11-04 06:48:49 · answer #3 · answered by tgypoi 5 · 0 0

n = m/MW
n = (40x10^-3)/MW
MW = relative molecular weight, so you need to know what substance you use
now, n = h mole
M = n/litre
M = molarity
M = h mole/(y litre of your solvent)
units for M = z mole/L (or also known as molar)
hence, M = z x 10^6 umole/L

2006-11-04 08:59:22 · answer #4 · answered by caren 2 · 0 0

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