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resolve

2006-11-03 21:58:56 · 5 answers · asked by bruno b 1 in Science & Mathematics Mathematics

5 answers

3x²-17x=-8
3x² - 17x + 8 = 0
3x² - 12x - 2x + 8 = 0
3x(x - 4) - 2(x-4)
(3x - 2)(x-4) = 0
Either 3x - 2 = 0
or x - 4 = 0
Put 3x - 2 = 0
3x = 2
x = 2/3
Put x - 4 = 0
x = 4
So x can be 4 or 2/3
The equation has two solutions

2006-11-04 03:47:31 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0 0

first, you have to bring the -8 to the LHS of the equation, so the equation is:

3x²-17x +8 = 0

then you apply the quadratic formula, where a = 3, b = -17, c = 8
once you get your answer you can simplify it further..but that depends on whether you've learnt complex numbers or not.

2006-11-03 22:19:16 · answer #2 · answered by thugster17 2 · 0 0

First put it in the standard form for a quadratic equation

3x²-17x+8 = 0

There is no nice factorization. You must use the quadratic formula:

x = [-b +/- sqrt(b² - 4ac) ] / 2a

for

ax² + bx + c = 0.

2006-11-03 22:08:11 · answer #3 · answered by Hal 2 · 0 0

3x²-17x=-8
=>3x²-17x+8=0
solving using general formula:
=>x=[17(+-)sqrt(289-96)]/6
=>x=[17(+-)sqrt(193)]/6

2006-11-03 22:03:33 · answer #4 · answered by sushant 3 · 0 0

3x² -17x +8 =0

x1=(17+√194)/6
x2=(17-√194)/6

2006-11-03 22:07:23 · answer #5 · answered by George 1 · 0 0

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