3x²-17x=-8
3x² - 17x + 8 = 0
3x² - 12x - 2x + 8 = 0
3x(x - 4) - 2(x-4)
(3x - 2)(x-4) = 0
Either 3x - 2 = 0
or x - 4 = 0
Put 3x - 2 = 0
3x = 2
x = 2/3
Put x - 4 = 0
x = 4
So x can be 4 or 2/3
The equation has two solutions
2006-11-04 03:47:31
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answer #1
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answered by Akilesh - Internet Undertaker 7
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first, you have to bring the -8 to the LHS of the equation, so the equation is:
3x²-17x +8 = 0
then you apply the quadratic formula, where a = 3, b = -17, c = 8
once you get your answer you can simplify it further..but that depends on whether you've learnt complex numbers or not.
2006-11-03 22:19:16
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answer #2
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answered by thugster17 2
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First put it in the standard form for a quadratic equation
3x²-17x+8 = 0
There is no nice factorization. You must use the quadratic formula:
x = [-b +/- sqrt(b² - 4ac) ] / 2a
for
ax² + bx + c = 0.
2006-11-03 22:08:11
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answer #3
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answered by Hal 2
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3x²-17x=-8
=>3x²-17x+8=0
solving using general formula:
=>x=[17(+-)sqrt(289-96)]/6
=>x=[17(+-)sqrt(193)]/6
2006-11-03 22:03:33
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answer #4
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answered by sushant 3
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3x² -17x +8 =0
x1=(17+â194)/6
x2=(17-â194)/6
2006-11-03 22:07:23
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answer #5
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answered by George 1
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