given C= 61 degrees, a=55, and b=29 the area of the triangle.?

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given C= 61 degrees, a=55, and b=29 the area of the triangle.?

2006-11-03 18:53:03 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

Area = ½ ab SinC
Area = ½(55)(29) Sin 61º
Area = ½(1595) Sin 61º
Area = 797∙5 Sin 61º
Area = 797∙5(0∙874 619 707)
Area = 697∙509 2165
Area ≈ 697∙51 square units.

2006-11-03 19:48:20 · answer #1 · answered by Brenmore 5 · 0⤊ 0⤋

Area is 1/2 ab Sin(C), or 1/2 (55)(29) Sin(61), or 697.509

2006-11-04 03:00:10 · answer #2 · answered by Scythian1950 7 · 0⤊ 0⤋

Area Formula

A = 1/2 ab sinÎ¸

A= 1/2(29)(55)sin61

A = 1/2(55)(29)(0.874619707)

A = 697.5092164

A = 697.5 Rounded to one decimal point

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2006-11-04 05:10:00 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋

area = 0.5 x a x b x sin C = 0.5 x 55 x 29 x 0.87462 = 697.5

2006-11-04 03:00:25 · answer #4 · answered by buaya123 3 · 0⤊ 0⤋