2006-11-03 16:19:49 · 5 answers · asked by JuggaletteCharm 2 in Education & Reference ➔ Homework Help
sorry i made an error... solve log 1/100 = log(10^x+2).... my bad
2006-11-03 16:30:37 · update #1
log 1/100 = log(10^(x+2))
(x+2)log10 = -log(100)
x + 2 = -2log(10)/log(10)
x = -4
1/100 = (10^x)+2 has no "real" solution, as log(-x) is undefined
2006-11-03 16:45:02 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
log(1/10^2) =log(10^(x+2)) so
10^-2 = 10^(x+2) and
-2 = x+2 so x = -4
2006-11-04 03:52:41 · answer #2 · answered by math maker 2 · 0⤊ 0⤋
The answer is -0.199
1/100 = 10X + 2 (then solve algebraically)
Sue
2006-11-04 00:45:30 · answer #3 · answered by newbiegranny 5 · 0⤊ 1⤋
i solved it with a TI89 and it is:
(ln(199/100)/(ln(10))+(2*@n1+1)*PI/ln(10)
well as you know PI= 3.14 but I don't really know what on earth @n1 might be but as I said this is what I got from solving the equation on a TI89.
why dont you use Matlab for solving it?
2006-11-04 00:36:22 · answer #4 · answered by Ali Amirshahi 3 · 0⤊ 1⤋
8
PS that is alright, young lady, but if you make those copying errors in math class, you may be in trouble.
2006-11-04 00:23:26 · answer #5 · answered by Anonymous · 0⤊ 1⤋