We can use the textbook results for head-on elastic collisions to analyze the recoil of the Earth when a ball bounces off a wall embedded in the Earth. Suppose a professional baseball pitcher hurls a baseball (m = 155 grams = 0.155 kg) with a speed of 98 miles per hour (vball = 43.1 m/s) at a wall, and the ball bounces back with little loss of kinetic energy.
(a) What is the recoil speed of the Earth (M = 61024 kg)?
(b) Calculate the recoil kinetic energy of the Earth and compare to the kinetic energy of the baseball. The Earth gets lots of momentum (twice the momentum of the baseball) but very little kinetic energy.
I think i could figure this out if I knew how to write up the energy principle equation. Either way, can someone please explain how to do this? I just wanna get this done (but also how i can do it of course)
Thanks everyone
2006-11-03
14:15:14
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2 answers
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asked by
jnieves01
1
in
Science & Mathematics
➔ Physics
Alright figured it out!
set it up as
p1+p2=p3+p4
p1 = initial momentum of ball
p2 = 0 (this is the wall)
p3 = initial momentum of ball, times 2 since it rebounds
p4 = solve for this to find rebound momentum of earth
These are all interchangeable with deltaK for energy changes, solved same way
Thanks for the suggestion on using conservation of momentum
2006-11-03
15:25:38 ·
update #1