Find the distance d(A, B) between the points A(-1, 0) and B(4,3).
2006-11-03 12:48:30 · 5 answers · asked by cil 1 in Science & Mathematics ➔ Mathematics
distance=sqrt((x1-x2)^2+(y1-y2)^2)
sqrt((-1-4)^2+(0-3)^2)=sqrt(34)=5.831
2006-11-03 12:52:31 · answer #1 · answered by mathpath 2 · 0⤊ 0⤋
Time to do some Pythagorean Theorm! Draw those points out on a graph then make a right triangle with the line between them forming the hypotenuse. You can also just figure this out in your head. One side of the triangle will be 5 units long (there is 5 units between -1 and 4) while the other side will be 3 units long (0 to 3 is 3 units).
Now do the Pythagorean theorem:
a^2 + b^2 = c^2 with a and b being two sides of the triangle and c being the third you are trying to figure out.
5^2 + 3^2 = c^2
25 + 9 = 34
Square root 34 and you get 4 + root(2) or
5.8309518948453
2006-11-03 20:55:47 · answer #2 · answered by Roman Soldier 5 · 0⤊ 0⤋
Hi. The distance is a relatively simple trig problem. You are looking for the hypotenuse of a triangle with the two adjacent sides described by the coordinates x= -1 and y= 0 to x= 4 and y= 3. Does this help?
2006-11-03 20:57:01 · answer #3 · answered by Cirric 7 · 0⤊ 0⤋
The formula for finding the distance between two points is
d=the sq. root of (Xsub2-Xsub1)^2+(Ysub2-Ysub1)^2
so....25+9=34.....take the square root of that and you get.....5.831
2006-11-03 21:00:12 · answer #4 · answered by Kelly 1 · 0⤊ 0⤋
let the points be A(x1,y1) and B(x2,y2) the distance d(A,B) is square root of(((x1-x2)*(x1-x2))+((y1-y2)*(y1-y2))).therefore the answer is 5.83095...
bye take care
2006-11-03 20:58:33 · answer #5 · answered by manoj 1 · 0⤊ 0⤋