what is the square root of 2x + 4, + 4 = 0?

Question

what is the square root of 2x + 4, + 4 = 0

Answer 1

6... depending on if you meant: y=(2x+4)^(1/2)+4... raising a funstion to the 1/2th, is equivilent to the square root... or if you meant y=(2x+4+4)^(1/2). then it is 3. you can graph functions with a calculator, or at this site: http://www.shodor.org/interactivate/activities/GraphSketcher/

Answer 2

x = 0

Answer 3

what do you mean by the "," in the equation?
Is it square root(2x + 4) + 4 = 0?
If yes, this is my answer:

square root (2x + 4) + 4 = 0
(2x + 4)^1/2 + 4 = 0

squared the whole equation,
[(2x + 4)^1/2 + 4 = 0]^2

and will cancel out 1/2 and 2,
(2x + 4) + 16 = 0
2x + 20 = 0
x = -20/2
x = -10

Answer 4

Do you want to solve for x.

Do you mean
The square root of (2x + 4 + 4) = 0

square root of 2x + 8 = 0

square root of (2(x + 4)) = 0 solve for x

x = -4
To check plug -4 back into original equation

The square root of (2(-4)+ 4 + 4) = 0 True
The square root of 0 = 0 True


OR

Do you mean

The square root of (2x + 4 )+ 4 = 0

This statement is false, so no solution

Answer 5

Do you mean roots?
Transpose 4 to RHS
sqrt (2x+4)=-4
Square both sides..
4x^2+16x+16=-4
4x^2+16x+12=0
x^2+4x+3=0
(x+3)(x+1)=0
x={-3,-1}

Answer 6

I am afraid I do not understand what you are asking.... details plz.

Answer 7

sorry don't know