what volume of 0.0584M Ba(OH)2 is required to neutralize exactly 10.15ml of 0.141M H3PO4?

Question

phosphoric acid contains three acidic hydrogen. detail explaination

Answer 1

I think that the equation is
3Ba(OH)2 + 2H3PO4 ---> Ba3(PO4)2 + 6H2O
but maybe the answer is
Ba(OH)2 + 2H3PO4 ---> Ba(H2PO4)2 + 2H2O
but no problem you can use the same way to calculate.

3Ba(OH)2 + 2H3PO4 ---> Ba3(PO4)2 + 6H2O
the moles of H3PO4 0.01015 * 0.141 = 1.43 * 10^-3
the moles of Ba(OH)2 needed : 1.43 * 10^-3 *3 / 2 = 2.145 * 10^-3
the volume of Ba(OH)2 needed : 2.145 * 10^-3 / 0.0584 = 0..03673 L = 36.73 ml