answer the question below?

Question

Three people each toss a penny at the same time. What is the probability that two people get the same side of the penny and the other person gets the opposite side?

Answer 1

Each individual toss is 1 / 2, a 50% probability.

The possibilities of all outcomes is 1 / (2 x 2 x 2), a 12.5% probability.

Only 2 possible outcomes do not meet the desired outcome (all heads, all tails).

2 x 12.5% is 25% (but that's the opposite of what you want)

100% - 25% = 75%

Answer 2

I'll help you do it yourself:

Call the sides H and T.

Write HHH to represent all three people getting H.
HHT for the first and second getting H, the third T.
HTH for ... etc

You should get 8 possibilities altogether. In how many of those are two the same and the other different?

The probability is the fraction you get by writing that number as numerator and 8 as denominator.

P.S. Of those answers above, only Bo Peep is correct, and has left you to do the last little step yourself to get the answer.
We have both assumed that it doesn't matter which two people are the ones with the same side. If the problem were to find the probability that, say, 2 and 3 are the same and 1 is different, then the answer would be less: There would be only two chances out of 8:
HTT and THH

Probability = 2/8 = 0.25

Answer 3

There are eight possible combinations (2 for the first coin*2 for the second*2 for the third) and the only two that won't work are HHH and TTT. That means six of the eight will work, so the probability is 6/8 or 3/4, or 75%.

Answer 4

Hi,

The probability that each person could get one side or the other is 1/2.

when you are combining probabilities with an and statement, you multiply the individual probabilities.

P(heads) = 0.50
P(tails) = 0.50

For three participants, P(1,2,3) = 1/2 * 1/2 * 1/2 = 1/8

Then look at the number of ways that the desired result can come about:

P(Heads, Heads, Tails)
= P(Heads,Tails, Heads)
= P(Tails, Heads, Heads)
= P(Tails, Tails, Heads)
= P(Tails, Heads, Tails)
= P(Heads, Tails, Tails) = 1/8.

Since there are 6 ways that can happen, we add them up,

P(two of one, one of other) = 6/8 =3/4

Answer 5

2/3

Answer 6

HHH
HHT
HTH
HTT
THH
TTH
THT
TTT <----all possibilities

There are six combinations that have two of one side and one of the other, the other two are all heads or all tails. So the probability is 6/8 = 3/4.

Answer 7

Technically, there is a 100% chance 2 people will get at least one side.

Answer 8

there's 3 out of 4 chances

Answer 9

3/4 or 75%

Answer 10

very high