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The energy of the electron of the hydrogen atom at the ground state equals:

E1 = -2.18x10^(-18) J

The energy of the electron of the hydrogen atom at the shell with n = 5 equals:

E5 = E1/5^2 = --2.18x10^(-18)/25 J = -8.72x10^(-20) J

So, to remove this electron from 1 hydrogen atom we need:

ΔE = 0 - (-8.72x10^(-20)) = 8.72x10^(-20) J

And to remove this electron from Na = 6.023x10^23 (1 mol) of hydrogen atoms we need:

ΔE * Na = 8.72x10^(-20) x 6.023x10^23 = 52,520.56 J or

52.56 kJ/mol (approx)

2006-11-03 10:41:13 · answer #1 · answered by Dimos F 4 · 0 0

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2016-10-21 05:23:45 · answer #2 · answered by carrera 4 · 0 0

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