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Can you solve and exlpain... I'll choose the best answer... if you do good... lol... good try... and time to let the brain excersie ;)

2006-11-03 09:10:48 · 5 answers · asked by curious_Me 1 in Science & Mathematics Mathematics

5 answers

Yes, you simply add the "parts" in the ratio, since each number is an equal proportion of the total, so:

12 + 5 + 1 = 18 parts

so each part is 1/18 of the total, or 1/18 of 144:

144 * 1/18 = 8

So, since each part represents 8 games, we know:

12 * 8 = 96 wins
5 * 8 = 40 losses
1 * 8 = 8 ties (draws)

Hope this helps! Best of luck

2006-11-03 09:15:32 · answer #1 · answered by disposable_hero_too 6 · 1 0

12 + 5 + 1 = 18, so you have 18 parts. Divide 144 by 18, and get 8, which is the number of games in each part. Then you know that 12 parts are wins, so 12*8 = 96 wins. 5 parts are losses, so 5*8 = 40 losses, and 1 part is ties, so 1*8 = 8 ties.

The question asks how many losses they had, so the answer is 40.

2006-11-03 09:17:42 · answer #2 · answered by sakuyatech 2 · 1 0

Your homework, I presume? If there ratio is 12:5:1, and they have played 144 games, then there is a factor by which to multiply each part of the ratio to determine their total wins or total losses or total ties. Ad 12, 5 and 1 to come up with 18. Divide that into their 144 game total to get 8. Multiply each number in their ration to find their total by W/L/T category. This gives you 96 wins, 40 losses and 8 ties, and these numbers all add up to 144.

2006-11-03 09:19:28 · answer #3 · answered by PoppaJ 5 · 1 0

Add the parts and divide the total to get your multiplier.
You have 12 + 5 + 1 parts (18).
So you multiply 5 times (144/18) to get the number of losses (40).

2006-11-03 09:13:49 · answer #4 · answered by Bo Peep 3 · 1 0

None were losses. A 12 to 5 win/loss ratio is damn good, so they are complete winners in my book.

2006-11-03 09:20:35 · answer #5 · answered by Dramlor 2 · 0 1

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