Plz help, how do u solve this equation???

Question

given the points p(0,4) and Q9(2,-1), caluclate the length of PQ?

correction: Q(2,-1)

Answer 1

You have to use the Pythagorean Theorem. It says the lengths of the two short sides of a right triangle squared, then added together, equal the length of the long side squared. Picture a triangle on your sheet of graph paper. One leg goes from point P straight left to 2,4. The second goes from 2,4 straight down to Q. The third connects P and Q and is the longest of the three legs. The length of the first leg is 2. The length of the second is 5 (or -5 if you like; it doesn't matter since we're fixing to square it). The lengths squared are 25 and 4. So the distance between P and Q squared is 29. The distance is root(29), which is 5.385. That's your answer.

Answer 2

This type of gemotery is called cartesian geometry. The length of PQ can be calculated by using the distance formula which is
sqrt((x2-x1)^2 + (y2-y1)^2). Now you have the points p (0,4) and Q(2,-1)

so plug these values in to the equation
sqrt((0-2)^2+(4-(-1))^2) = sqrt(4+25) = sqrt(29). = 5.385 this is the answer.

Answer 3

The distance formula is √((x2-x1)²+(y2-y1)²), which is just an application of Pythagoreas' theorem.

Therefore PQ = √((2-0)²+(-1-4)²)
=√(2²+(-5)²)
=√(2²+(-5)²)
=√(4+25)
=√29
= approximately 5.4

Answer 4

given 2 points P(x1, y1) and Q (x2 ,y2)
the distance between them is given by the
square root of[ ( x1-x2)^2+ (y1-y2)^2.]

thus for the example. squareroot[(0-2)^2 + (4- -1)^2]

squareroor [(-2)^2 +(5)^2]
=
squareroot[4+25]
=squareroot[29]
=5.38

Answer 5

distance formula: sqrt[(x1-x2)^2+(y1-y2)^2]
sqrt[(0-2)^2+(4+1)^2]
=sqrt[29]

you can draw a right triangle and use the pathagorean theorem to see how this works.

Answer 6

Length = SQRT[ (x2 - x1)^2 + (y2 - y1)^2]

Plug the numbers.

Answer 7

This formula will get you the answer --> http://library.thinkquest.org/10030/6dbp.htm