A freight train has a mass of 1.6 107 kg. If the locomotive can exert a constant pull of 8.5 105 N, how long does it take to increase the speed of the train from rest to 70 km/h?
2006-11-03 07:28:09 · 3 answers · asked by Tennis2127 2 in Science & Mathematics ➔ Physics
Given: m=1.6*10^7kg
F=8.5*10^5N
I only guessed that the above is what you meant.
Solve for a, using the formula:
F=Ma
8.5*10^5=1.6*10^7a
a=8.5*10^5/1.6*10^7
=5.31*10^-2m/s^2
v=70km/h =70*1000/3600m/s
=19.44m/s
u=0
To solve for time, t, use the formula:
v=u+at
19.44=0+5.31*10^-2t
t=19.44/5.31*10^-2
=3.66*10^2
=366s
2006-11-03 18:08:02 · answer #1 · answered by tul b 3 · 0⤊ 0⤋
to help a little more. Here are the formulas u need.
Force = mass times acceleration F = ma
acceleration = velocity divided by time a = v/t
2006-11-03 15:49:05 · answer #2 · answered by ojmoo 4 · 0⤊ 0⤋
You have mass and force to get acceleration. divide velocity by acceleration to get time
2006-11-03 15:34:06 · answer #3 · answered by arbiter007 6 · 0⤊ 0⤋