12 balls 11 of which are all exactly the same weight - the other one is either heavier or lighter.
In 3 weighings using an ordinary balance find the odd ball and whether it is lighter or heavier.
2006-11-03 07:21:11 · 5 answers · asked by Goggie 3 in Games & Recreation ➔ Other - Games & Recreation
Six on each side, discard the lighter half.
3 on each side - discard the lighter half.
put one on each side - keep one in your hand.
If they balance, the one in your hand is heaviest.
If not, then the one on the lower scale is the heaviest.
2006-11-03 07:30:15 · answer #1 · answered by spiegy2000 6 · 0⤊ 0⤋
Use "Divide and Conquer" approach (from computer programming). Weigh six on each side first, remove the lighter side. Weigh three on each side, if the scale balances, you know that the odd bearing was in the heavier six, and is thus heavier than all the rest. If the scale tips, remove the lighter ones, and weigh again. By the third time, you will determine the answer.
2006-11-03 09:04:19 · answer #2 · answered by AllIWant2Know 1 · 0⤊ 1⤋
Check the ball diameter of all balls.
Take out the one which is having a lesser /more diameter.
Weigh all the other balls which are only 10 out of 11 balls by placing 5 in each of the balance.
They will balance.
Now take out one ball from the 5.
Put the 11 ball and take out one ball from the 10 you have weighed.
Put the 11 ball now in one of the 5 balls.
Weigh.
You got it.
2006-11-03 07:35:16 · answer #3 · answered by SKG R 6 · 0⤊ 1⤋
yeah i did it
2006-11-05 08:00:54 · answer #4 · answered by Jumble 4 · 0⤊ 1⤋
where the question in that?
2006-11-03 07:25:18 · answer #5 · answered by Courtney 2 · 0⤊ 2⤋