3.(6s5)(2s2) (3s4)(4s3)?

Question

12s10 12s12

B.
5s7

C.
1

D.
none of these

Answer 1

Please show your exponents using the ^ operator: It will make these problems much clearer. Also, I would have put this in 'Mathematics' rather than Chemistry.

First equation:
(6s^5)(2s^2)

Group your integer coefficients:
6*2 = 12

Group your s terms:
s^5 * s^2 = s^7 (multiplying like bases, just add the exponents)

Second equation:
(3s^4)(4s^3)

Multiply integers:
3 * 4 = 12

Multiply s terms (add exponents):
s^4 * s^3 = s^7

So your answers should both be:
12 s^7

Answer 2

If these are atomic orbitals, then the only one possible is 2s2. The s orbital can only contain a maximum of 2 electrons.
p can hold 6
d an hold 10
f can hold 14

Answer 3

What are you doing????? We need more information here!!