remember BODMAS
Brackets-Of-Division-Multiply-Add-Subtract
=1*(2 + 19 + 4*2/5 - 3)/ 1
=1*(2 + 19 + 8/5 - 3)/ 1
=1*(2 + 19 + 1.6 - 3)/ 1
=19.6
2006-11-03 06:47:06
·
answer #1
·
answered by ludacrusher 4
·
1⤊
0⤋
1* ( 2+19+4*2/5-3)/1 = 2+19+4*2/5-3 = 18 + 8/5
2006-11-03 14:46:00
·
answer #2
·
answered by Vladimir S 2
·
0⤊
0⤋
1 * anything is itself, and anything divided by 1 is itself, so we can drop those:
Multiplication and division first:
2 + 19 + 4 * 2 / 5 - 3 =
2 + 19 + 8 / 5 - 3 =
Then addition and subtraction:
2 + 19 + 1.6 - 3 = 19.6
Now, if you meant to have some of those operations in another order, you have to use parentheses. For example:
1* ( 2+19+4*2/(5-3))/1
Would be worked out this way:
2 + 19 + 8/2 =
2 + 19 + 4 = 25
2006-11-03 14:55:12
·
answer #3
·
answered by Dave 6
·
0⤊
0⤋
1* ( 2+19+4*2/5-3)/1=21+8/5-3=19.6
2006-11-03 15:05:59
·
answer #4
·
answered by yupchagee 7
·
0⤊
0⤋
1 has no relevence in this case its the same as saying
2+19+4*2/5-3
21+8/5-3
do the rest yourself
2006-11-03 14:45:37
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
25
2006-11-03 14:56:08
·
answer #6
·
answered by CV 1
·
0⤊
0⤋