2.(r2s)(3rs3)(s2)?

Question

A.
3r2s5

B.
r3s6

C.
3r3s6

D.
none of these

Answer 1

Can we assume you mean:
(r²s)(3rs³)(s²)?

Essentially you just need to group all your numbers first and multiply them. In this case you only have the 3, so remember a 3.

Now group all your r terms (r², r). When you multiply two terms with the same base, you can just add the exponents. That means you have r³. "r cubed"

Finally group all your s terms (s, s³, s²). Again add the exponents (1 + 3 + 2) to get s^6. I can't show you the 6 superscript, but the ^ means superscript. "s to the 6th power".

Putting it all together you have:
3 "r cubed" "s to the 6th"

C) 3 r³ s^6

Answer 2

(r2s)(3rs3)(s2)=r2s3rs3s2 none of these

Answer 3

(r2s)(3rs3)(s2)
3r^3s^6

C is correct

Answer 4

wht the hell is this?