I figured it out. See what ou get...You chemistry Lovers!
2006-11-03 03:43:45 · 5 answers · asked by nst 1 in Science & Mathematics ➔ Chemistry
nitrogen & hydrogen react to give ammonia according to the reaction
N2 + 3H2 -> 2NH3
according to the above reaction 1 & 3 moles of N2 & H2 respectively react to give 2 moles of NH3.
so, 6 moles ammonia can be produced by reacting 3 moles N2 & 9 moles H2.
2006-11-03 04:28:32 · answer #1 · answered by Anonymous · 1⤊ 0⤋
To answer this analytically, setup a system of linear equations:
a * H2 + b*N2 = 6*N*H3
Your equations for H is:
2*a = 3*6
2*b = 1*6
Clearly, a = 3*6/2 = 9 and b = 6/2 = 3.
Therefore the answer is 9 moles of H2 and 3 moles of N2 to produce 6 moles of NH3.
2006-11-03 04:31:54 · answer #2 · answered by Ted 4 · 0⤊ 0⤋
3 H2 + N2 ---> 2 NH3
Times each by 3.
9 moles H2 + 3 moles N2 gives 6 moles NH3
2006-11-03 04:01:38 · answer #3 · answered by David K 2 · 1⤊ 0⤋
from the equation 3moles of H2 will produce 2 moles of NH3 for this reason 9.5 moles of H2 will produce x molesf NH3 (x/9.5) = (2/3) x = (2/3)9.5 = 19/3 = 6.333 for this reason 9.5 moles of H2 will react to type 6.3 moles of NH3.
2016-10-21 05:01:30 · answer #4 · answered by ? 4 · 0⤊ 0⤋
Well if you figured it out, then I don't know I am answering, but... if you wanna compare... here is mine.
9H2 + 3 N2 --> 6 NH3 so the tallies work that on the left side of the equation you've got 18 Hs and 6 Ns and on the right side, you've got the same. Balanced moles.
2006-11-03 04:40:20 · answer #5 · answered by summation 2 · 0⤊ 0⤋