Find the distance between (–4, 0) and (–5, –3)?

Question

I came up with 3sqrt 10

Is that right?

Answer 1

Listen to the first guy.
The distance on the y axis is 1 ((-5)-(-4)) and on the x axis it is 3 ((-3)-0).
This gives you a right angles triangle with sides of 3 & 1.
Under Pythagoras theoem the sum of the squares is equal to the square of the hypoteneuse so
1^2 + 3^2 = 10.
Therefore the distance is the square root of 10.

Answer 2

No Dear, you are wrong,

-4, 0 is a point on x axis at a distance of - 4 and -5,-3 is a point in 3rd quadrent at -5 in x and -3 in y. now conect this two point. and draw a triangle by drwing line paralel to x and y axis. you are getting a triang having base of 1 unit and height of 3 unit. so h your reqired distance will be './'''''1+9 = ./'''''10. using formulla h.sq=b.sq.+p.sq. (Under Pythagoras theoem the sum of the squares is equal to the square of the hypoteneuse so
1^2 + 3^2 = 10.)


so ans is under root 10

Answer 3

d^2=(-3-0)^2+(-5+4)^2=9+1=10
d=rt10

Answer 4

Not quite right. It should just be sqrt10.

Answer 5

root10