2006-11-03 01:28:30 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
49*x^2-16=0
(7*x)^2-(4)^2=0
(7*x-4)(7*x+4)=0
7x=4,7x=-4
x=4/7,x=-4/7.
2006-11-03 06:20:48 · answer #1 · answered by Anonymous · 0⤊ 0⤋
X^2=16/49
X=+-4/7
2006-11-03 13:41:07 · answer #2 · answered by openpsychy 6 · 0⤊ 0⤋
49x² - 16 = 0
49x² - 16 + 16 = 0 + 16
49x² = 16
49x² / 49 = 16 / 49
x² = â16 / 49
x = ± 4 / 7
The answer is x = ± 4 / 7
- - - - - - -s-
2006-11-03 10:20:00 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
add 16 to both sides
49x^2=16
divide both sides by 49
x^2=16/49
take the square root of both sides
x=+/- 4/7
2006-11-03 09:30:56 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Either you are super smart and sees the decomposition others have pointed out: (7-4x)*(7+4x) = 0.
Or just treat it as a general quadratic eq: ax^2 + bx + c =0
x = -b +- sqrt(b^2 - 4ac) / 2a, where a = 49, b = 0, c = -16
sqrt(-4ac) = sqrt(49*16) = 7*4
the two roots are: x = 7*4/2*49 = 47 and -4/7.
2006-11-03 13:48:39 · answer #5 · answered by eatdrinkmanwoman 1 · 0⤊ 0⤋
1) add 16 to both sides of the equation
49(x)^2 = 16
2) Divide both sides by 49
(x)^2 = 16/49
3) Take the square root of 16/49
which is + or - 4/7
2006-11-03 09:35:40 · answer #6 · answered by Centurion 2 · 0⤊ 0⤋
49x^2-16 = (7x - 4)(7x + 4)
since the equation is equal to zero, either 7x - 4 or 7x + 4 is equal to zero
7x - 4 = 0
x = 4/7
7x + 4 = 0
x = - 4/7
2006-11-03 10:33:59 · answer #7 · answered by J Go 2 · 0⤊ 0⤋
presume the equation is 49*(square of x)-16=0.
Then, square of x = 16/49 and
x= square-root of (16/49)= 4/7
2006-11-03 09:34:32 · answer #8 · answered by r_ravoori 2 · 0⤊ 0⤋
49X2-16=0
49x2=16
square root of 49x=square root of 16
7x=4
x=(4/7)
square root porperty of zeros
2006-11-03 09:36:50 · answer #9 · answered by Jdicu812 1 · 0⤊ 0⤋
x=4/7=0.571428571429
2006-11-03 09:40:00 · answer #10 · answered by Anonymous · 0⤊ 0⤋