sin(B+2C)+sin(C+2A)+sin(A+2B)=4sin(B-C/2)sin(C-A/2)sin(A-B/2)
2006-11-03 00:24:28 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
compleate the question
2006-11-03 00:31:32 · answer #1 · answered by . 3 · 0⤊ 0⤋
sin(x+y) = sin(x)cos(y) + sin(y)cos(x)
cos(x+y) = cos(x)cos(y) - sin(x)sin(y)
sin(2x) = sin(x+x) = 2sin(x)cos(x)
cos(2x) = cos²(x) - sin²(x) = 2cos²(x) - 1 = 1 - 2sin²(x)
First term is
sin(B+2C) = sin(B)cos(2C) + sin(2C)cos(B) =
sin(B) - 2sin(B)sin²(C) + 2sin(C)cos(C)cos(B)
Apply repeatedly, collect terms, and simplify using algebra and the identities as required âº
Doug
2006-11-03 08:46:02 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
What do you mean by ...
2006-11-03 08:34:46 · answer #3 · answered by bhen 3 · 0⤊ 0⤋
can you give the right hand side please?
2006-11-03 08:32:35 · answer #4 · answered by raj 7 · 0⤊ 0⤋