No fractions. It's like 4th Grade Level.
Factor: What the number can be divided by with no remainder.
I need to find a number that can be divided by 12 numbers.
THE NUMBER 60 CAN NOT BE USED!
For example:
The factors of 60:1,2,3,4,5,6,10,12,15,20,30,60
60 CAN NOT be the number used.
It's just an example.
Please help if you can!
2006-11-03 00:15:58 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
60 is the smallest number that has exactly 12 factors.
The next numbers under 100 are 72, 84, 90 and 96.
72 : 1 2 3 4 6 8 9 12 18 24 36 72
84 : 1 2 3 4 6 7 12 14 21 28 42 84
90 : 1 2 3 5 6 9 10 15 18 30 45 90
96 : 1 2 3 4 6 8 12 16 24 32 48 96
2006-11-03 00:55:53 · answer #1 · answered by falzoon 7 · 2⤊ 0⤋
72
1 2 3 4 6 8 9 12 18 24 36 72
2006-11-03 00:23:37 · answer #2 · answered by bob h 3 · 2⤊ 0⤋
Assuming you want numbers with exactly 12 factors, then
72 is the smallest one after 60, as others have pointed out. Falzoon correctly lists the ones that follow. More generally, a number has exactly 12 factors if its prime factorization is one of the following, where p, q, and r are prime numbers:
p^2 * q * r (example: 84)
p^3 * q^2 (ex: 72)
p^5 * q (ex: 96)
p^11 (ex: 2048)
2006-11-03 01:18:01 · answer #3 · answered by Anonymous · 1⤊ 0⤋
This number can be:
13!=1*2*3*4*5*6*7*8*9*10*11*12=6227020800,
you can divide it by any number between 1 and 12, even by 13, but you can't use it.
Of course, you can divide it by a far more factors, but it will blow out your teachers mind the fact you can divide it by a sequence of factors!
2006-11-03 00:20:45 · answer #4 · answered by El calvito 3 · 0⤊ 2⤋
You didn't specify the maximum number. There's a plenty of number that can be divided by 12 numbers without remainders.
Is this okay?
72 has the ff factors:
1,2,3,4,6,8,9,12,18,24,36,72
2006-11-03 00:33:18 · answer #5 · answered by bhen 3 · 2⤊ 0⤋
I assume you mean can divided by exactly 12 numbers
2*3 // 1,2,3,6
2*3*5 // 1,2,3,6,5,10,15,30
2*3*5*7 // exactly 12 including 1 and the number itself
2006-11-03 00:57:00 · answer #6 · answered by ramesh the great 1 · 0⤊ 2⤋
Since the problem, as stated, does not preclude the repeated use of any single value, I would submit that *any* numbers can be used since any positive, integer value can be divided 12 times by 1.
Doug
2006-11-03 00:26:38 · answer #7 · answered by doug_donaghue 7 · 0⤊ 1⤋
A one with twelve zeros behind it (1,000,000,000,000).
It can be divided by 1, 10, 100, 1000, 10000, etc.
2006-11-03 00:22:42 · answer #8 · answered by Anonymous · 0⤊ 2⤋
The product of the first twelve prime numbers would qualify, but it is not the smallest such number.
2006-11-03 00:19:52 · answer #9 · answered by Anonymous · 0⤊ 0⤋
1,2,4,5,10,20,25,50,100,200,300,400,500
2006-11-03 00:19:51 · answer #10 · answered by i_luv_new_york_120060 1 · 1⤊ 2⤋